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求函数u=ArCtAnx∧2+x∧(y+z×z),求Du

∂u/∂x=2x/(1+x^4)+(y+z^2)x^(y+z^2 -1), ∂u/∂y=x^(y+z^2)•lnx, ∂u/∂z=x^(y+z^2)•lnx•2z, du=[2x/(1+x^4)+(y+z^2)x^(y+z^2 -1)]dx+[x^(y+z^2)•lnx]dy+[x^(y+z^2)•lnx•...

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