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42X[169-(78+35)]=多少.脱式计算

42x[169-(78+35)] =42×【169-113】 =42×56 =2352

42×(169-113)=42×56=2352

78十35x30÷5 =78+1050÷5 =78+210 =288

(90-35)+78÷13 =(90-35)+6 =55+6 =61

解答: 解:①35×46-854,=1610-854,=756;②86×25×4,=86×(25×4),=86×100,=8600;③(126-78)×75,=48×75,=3600.

155-(35.78+1.23) =155-37.01 =117.99

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